是否看到别人的网站网址名都不带后缀名比较酷，比如qq空间的地址，其实用urlrewrite这个包很容易就实现了。
    下面是使用说明：

1.下载urlrewrite 2.6,下载地址

2.解压缩文件，压缩包内文件copy到项目中(压缩包位置 -> 项目位置)：

urlrewrite-2.6.0-src/webapp/WEB-INF/lib/urlrewrite-2.6.0.jar -> WebRoot/WEB-INF/lib/urlrewrite-2.6.0.jar

urlrewrite-2.6.0-src/webapp/WEB-INF/urlrewrite.xml -> WebRoot/WEB-INF/urlrewrite.xml
3.将以下代码添加到web.xml里

Xml代码
<filter>  
        <filter-name>UrlRewriteFilter</filter-name> 
 
        <filter-class>  
            org.tuckey.web.filters.urlrewrite.UrlRewriteFilter   
        </filter-class>  
    </filter>  
    <filter-mapping>  
        <filter-name>UrlRewriteFilter</filter-name>  
        <url-pattern>/*</url-pattern>  
    </filter-mapping> 
<filter>
        <filter-name>UrlRewriteFilter</filter-name>
        <filter-class>
            org.tuckey.web.filters.urlrewrite.UrlRewriteFilter
        </filter-class>
    </filter>
    <filter-mapping>
        <filter-name>UrlRewriteFilter</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>
4.修改urlrewrite.xml

Xml代码
<?xml version="1.0" encoding="utf-8"?>    
<!DOCTYPE urlrewrite PUBLIC "-//tuckey.org//DTD UrlRewrite 2.6//EN"    
"http://tuckey.org/res/dtds/urlrewrite2.6.dtd">    
  
<!--    
  
Configuration file for UrlRewriteFilter    
http://tuckey.org/urlrewrite/    
  
-->    
<urlrewrite>    
    <rule>    
        <from>^/([a-z]+)$</from>    
        <to type= "forward" >/world.jsp?id=$1</to>    
    </rule>    
    <rule>  
        <from>^/world/(.*)$</from>  
        <to>/world.jsp?tid=$1</to>  
    </rule>  
    <rule>  
        <from>^/(.*).html$</from>  
        <to>/test1/$1.jsp</to>  
    </rule>  
       
    <outbound-rule>    
        <note>    
        The outbound-rule specifies that when response.encodeURL is called (if you are using JSTL c:url)    
        the url /rewrite-status will be rewritten to /test/status/.    
           
        The above rule and this outbound-rule means that end users should never see the    
        url /rewrite-status only /test/status/ both in thier location bar and in hyperlinks    
        in your pages.    
        </note>    
        <from>/rewrite-status</from>    
        <to>/test/status/</to>    
    </outbound-rule>  
</urlrewrite>  
<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE urlrewrite PUBLIC "-//tuckey.org//DTD UrlRewrite 2.6//EN"
"http://tuckey.org/res/dtds/urlrewrite2.6.dtd">

<!--

Configuration file for UrlRewriteFilter
http://tuckey.org/urlrewrite/

-->
<urlrewrite>
 <rule>
  <from>^/([a-z]+)$</from>
  <to type= "forward" >/world.jsp?id=$1</to>
 </rule>
 <rule>
     <from>^/world/(.*)$</from>
     <to>/world.jsp?tid=$1</to>
 </rule>
 <rule>
  <from>^/(.*).html$</from>
  <to>/test1/$1.jsp</to>
 </rule>
 
 <outbound-rule>
  <note>
  The outbound-rule specifies that when response.encodeURL is called (if you are using JSTL c:url)
  the url /rewrite-status will be rewritten to /test/status/.
  
  The above rule and this outbound-rule means that end users should never see the
  url /rewrite-status only /test/status/ both in thier location bar and in hyperlinks
  in your pages.
  </note>
  <from>/rewrite-status</from>
  <to>/test/status/</to>
 </outbound-rule>
</urlrewrite>

rule是url重写规则,from是显示出来的地址,to是映射的实际地址,$1是重写参数,可以为多个,()里是匹配的正则表达式.
好了,在项目中新建world.jsp,启动tomcat,输入
http://localhost:8080/mysite/world/1

mysite是你的项目名

实际上访问的是http://localhost:8080/mysite/world.jsp?tid=1